c语言-17题

晓嘿君2025-03-242025-03-28

2025年3月24日

1. 统计及格人数及平均分

#include <stdio.h>
int main() {
    float score, sum=0;
    int i=1, k=0; // k记录及格人数，sum记录总分
    while(i <= 10) {
        scanf("%f", &score);
        if(score >= 60) {
            k = k + 1;
            sum = sum + score;
        }
        i = i + 1;
    }
    printf("及格人数：%d，平均分：%f", k, sum/k);
    return 0;
}

2. 统计及格与不及格人数及平均分

#include <stdio.h>
int main() {
    float score, sum_jige=0, sum_bujige=0;
    int i=1, k=0, m=0; // k及格人数，m不及格人数
    while(i <= 10) {
        scanf("%f", &score);
        if(score >= 60) {
            k = k + 1;
            sum_jige = sum_jige + score;
        } else {
            m = m + 1;
            sum_bujige = sum_bujige + score;
        }
        i = i + 1;
    }
    printf("及格人数：%d，平均分：%f\n", k, sum_jige/k);
    printf("不及格人数：%d，平均分：%f", m, sum_bujige/m);
    return 0;
}

3. 统计优良、及格、不及格信息

#include <stdio.h>
int main() {
    float score, sum_you=0, sum_ji=0, sum_bu=0;
    int i=1, you=0, ji=0, bu=0;
    while(i <= 10) {
        scanf("%f", &score);
        if(score >= 80) {
            you = you + 1;
            sum_you = sum_you + score;
        } else if(score >= 60) {
            ji = ji + 1;
            sum_ji = sum_ji + score;
        } else {
            bu = bu + 1;
            sum_bu = sum_bu + score;
        }
        i = i + 1;
    }
    printf("优良：%d人，平均分：%f\n", you, sum_you/you);
    printf("及格：%d人，平均分：%f\n", ji, sum_ji/ji);
    printf("不及格：%d人，平均分：%f", bu, sum_bu/bu);
    return 0;
}

4. 统计各等级人数

#include <stdio.h>
int main() {
    int score, i=1, you=0, ji=0, bu=0;
    while(i <= 10) {
        scanf("%d", &score);
        if(score >= 80) {
            you = you + 1;
        } else if(score >= 60) {
            ji = ji + 1;
        } else {
            bu = bu + 1;
        }
        i = i + 1;
    }
    printf("优良：%d人\n及格：%d人\n不及格：%d人", you, ji, bu);
    return 0;
}

5. 输出3或7的倍数（每行10个）

#include <stdio.h>
int main() {
    int i=1, count=0;
    while(i <= 100) {
        if(i % 3 == 0 || i % 7 == 0) {
            printf("%d ", i);
            count = count + 1;
            if(count % 10 == 0) {
                printf("\n");
            }
        }
        i = i + 1;
    }
    printf("\n总共有%d个", count);
    return 0;
}

6.1 计算m到n的奇数和

#include <stdio.h>
int main() {
    int m, n, sum=0;
    scanf("%d %d", &m, &n);
    int current = m;
    while(current <= n) {
        if(current % 2 != 0) {
            sum = sum + current;
        }
        current = current + 1;
    }
    printf("奇数和：%d", sum);
    return 0;
}

6.2 统计能被17整除的数的和

#include <stdio.h>
int main() {
    int m, n, sum=0;
    scanf("%d %d", &m, &n);
    int current = m;
    while(current <= n) {
        if(current % 17 == 0) {
            sum = sum + current;
        }
        current = current + 1;
    }
    printf("和：%d", sum);
    return 0;
}

7. 求正整数的因数

#include <stdio.h>
int main() {
    int num, i=1, count=0, sum=0;
    scanf("%d", &num);
    printf("因数：");
    while(i <= num) {
        if(num % i == 0) {
            printf("%d ", i);
            count = count + 1;
            sum = sum + i;
        }
        i = i + 1;
    }
    printf("\n个数：%d，总和：%d", count, sum);
    return 0;
}

8. 统计1、5、10的出现次数

#include <stdio.h>
int main() {
    int n, num, i=1, c1=0, c5=0, c10=0;
    scanf("%d", &n);
    while(i <= n) {
        scanf("%d", &num);
        if(num == 1) c1 = c1 + 1;
        else if(num == 5) c5 = c5 + 1;
        else if(num == 10) c10 = c10 + 1;
        i = i + 1;
    }
    printf("1出现：%d次\n5出现：%d次\n10出现：%d次", c1, c5, c10);
    return 0;
}

9. 找出符合条件的四位数

#include <stdio.h>
int main() {
    int num=1000, count=0;
    while(num <= 9999) {
        int a = num / 1000;
        int b = (num / 100) % 10;
        int c = (num / 10) % 10;
        int d = num % 10;
        if(d - a - b - c > 0) {
            printf("%d ", num);
            count = count + 1;
        }
        num = num + 1;
    }
    printf("\n共有%d个", count);
    return 0;
}

10. 输出水仙花数

#include <stdio.h>
int main() {
    int num=100, count=0;
    while(num <= 999) {
        int a = num / 100;
        int b = (num / 10) % 10;
        int c = num % 10;
        if(a*a*a + b*b*b + c*c*c == num) {
            printf("%d ", num);
            count = count + 1;
        }
        num = num + 1;
    }
    printf("\n水仙花数共有%d个", count);
    return 0;
}

11. 输出100-200的回文数

#include <stdio.h>
int main() {
    int num=100, count=0;
    while(num < 200) {
        int a = num / 100;
        int c = num % 10;
        if(a == c) {
            printf("%d ", num);
            count = count + 1;
        }
        num = num + 1;
    }
    printf("\n回文数共有%d个", count);
    return 0;
}

12. 统计字符类型（输入10个字符）

#include <stdio.h>
int main() {
    int i=0, letter=0, space=0, digit=0, other=0;
    char ch;
    while(i < 10) {
        scanf(" %c", &ch); // 空格跳过换行符
        if((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
            letter = letter + 1;
        } else if(ch >= '0' && ch <= '9') {
            digit = digit + 1;
        } else if(ch == ' ' || ch == '\n') {
            space = space + 1;
        } else {
            other = other + 1;
        }
        i = i + 1;
    }
    printf("字母：%d，数字：%d，空格：%d，其他：%d", letter, digit, space, other);
    return 0;
}

13. 求sum首次超过100时的n

#include <stdio.h>
int main() {
    int n=0, sum=0;
    while(sum <= 100) {
        n = n + 1;
        sum = sum + n;
    }
    printf("n=%d，sum=%d", n, sum);
    return 0;
}

14. 找最小x使a,b,c同余

#include <stdio.h>
int main() {
    int a, b, c, x=2;
    scanf("%d %d %d", &a, &b, &c);
    while(1) {
        if(a % x == b % x && b % x == c % x) {
            printf("%d", x);
            break;
        }
        x = x + 1;
    }
    return 0;
}

15. 找最大值和最小值

#include <stdio.h>
int main() {
    int num, min=1000, max=0;
    printf("输入若干整数（输入非数字结束）：");
    while(scanf("%d", &num) == 1) {
        if(num < min) min = num;
        if(num > max) max = num;
    }
    printf("最小值：%d，最大值：%d", min, max);
    return 0;
}

16. 判断m是否符合条件

#include <stdio.h>
int main() {
    int m, k, count3=0, temp;
    scanf("%d %d", &m, &k);
    temp = m;
    while(temp > 0) {
        int digit = temp % 10;
        if(digit == 3) count3 = count3 + 1;
        temp = temp / 10;
    }
    if(m % 19 == 0 && count3 == k) {
        printf("YES");
    } else {
        printf("NO");
    }
    return 0;
}

17. 统计与指定数字相同的个数

#include <stdio.h>
int main() {
    int n, m, num, count=0, i=0;
    scanf("%d %d", &n, &m);
    while(i < n) {
        scanf("%d", &num);
        if(num == m) count = count + 1;
        i = i + 1;
    }
    printf("%d", count);
    return 0;
}